Find the area of the regular polygon. Round to the nearest tenth.

7 yd

[? ] yd?

98 yd²

Step-by-step explanation:

From the diagram attached, The polygon is a square with the distance from the edge of the square to the center of the square = 7 yd.

The distance from the edge of the square to the center of the square is half of the diagonal. Therefore length of the diagonal = (7 yd * 2) = 14 yd

The diagonal and two sides of the triangle form a right angle triangle. Let the side of the triangle be a. Therefore the hypotenuse is the diagonal, using Pythagoras theorem:

a² + a² = 14²

2a² = 196

a² = 98

a = √98 = 7√2

The length of the side of the triangle = a = 7√2 yd

The area of the rectangle = length × length = 7√2 × 7√2  = 98 yd²

7

step-by-step explanation: