What is the center and radius of the circle? (x-4)^2 + (y-7)^2 =49

Step-by-step explanation:

First expand the equation

That's

( x - 4)² + ( y - 7)² = 49

x² - 8x + 16 + y² - 14y + 49 - 49 = 0

x² + y² - 8x - 14y + 16 = 0

Comparing with the general equation of a circle

x² + y² + 2gx + 2fy + c = 0

2g = - 8 2f = - 14

g = - 4 f = - 7 c = 16

Center of a circle is ( - g , - f)

( --4 , --7)

Which is ( 4 , 7)

The radius of the circle is given by

r = √g² + f² - c

Where r is the radius

r = √ (-4)² + (-7)² - 16

= √16 + 49 - 16

= √49

Hope this helps you

answer

see attachment

explanation

the given function is

this function has y-intercept at

-4 and a slope of 2.

note that, the graph has a positive slope.

the graph that represents this function is the straight line that moves upward from left to right.

the graph touches the y-axis at -4.

the correct choice is the graph shown in the attachment.

x = ±sqrt(10)

step-by-step explanation:

5 - 2x² = -15

subtract 5 from each side

5-5 - 2x² = -15-5

-2x^2   = -20

divide by -2 on each side

-2x^2   /-2= -20/-2

x^2 =10

take the square root on each side

sqrt(x^2 )=±sqrt(10)

x = ±sqrt(10)

check:

5 - 2x² = -15

+sqrt(10)

5 - 2(sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15

-sqrt(10)

5 - 2(-sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15