Now that the curve pieces are determined, use those pieces as sections of a complete coaster. By hand or by using a drawing program, sketch a design of Ray and Kelsey's coaster that includes the shape of the g(x) and f(x) functions that you chose in the Parts A and B. You do not have to include the coordinate plane. You may arrange the functions in any order you choose, but label each section of the graph with the corresponding function for your instructor to view. THAT'S THE QUESTION, I NEED HELP WITH

Step-by-step explanation:

Both Ray and Kelsey could be right if we inculded imaginary numbers.

My choice : g(x) = (x+3) (x+2) (x-3)

The linear factor form can tells us easily the zeros wich are

Replace x by 0

g(0) = (0+3)(0+2)(0-3) = 3*2*(-3) = -18

so the y intercept is at (0,-18)

g(x) = (x+3)(x+2)(x-3) = (x²-9)(x+2) = x^3 +2x²-9x-18

+∞

∞

An image of the graph is available:

the function I have chosen last time is x²-3x+2

a graph of it is also available

I included also a graph for both functions

with a design for the coaster

step-by-step explanation:

use pothagarean therom

a^2+b^2=c^2 so first ac

acm is a right triangle because c= 90°

and am (the hypotenuse or c) =16+9 =25

but there is not enough info we need another angle or side length

second option

step-by-step explanation:

the measures of a triangle equal 180. use that to find x.

2x+3x+4x=180

9x=180

9x/9=180/9

x=20

now you know x, you know angle a is 40°, angle b is 60°, angle c is 80°.

because angle a is 40°, the first option doesn't work.

because angle b is 60°, the second option does work.

when you add angle a and b, you get 100°. complementary means it equals 90°, so the third option doesn't work.

when you add angle a and c, you get 120°, which is not 100.