Given: F={(0, 1), (2, 4), (4, 6), (6, 8)} and G = {(2, 5), (4,7), (5, 8), (6,9). (7.5)) (F. G) (2) =
10
O 20
O 40

  (F·G)(2) = 20

Step-by-step explanation:

We assume you want (F·G)(2).

  (F·G)(2) = F(2)·G(2)

  F(2) = 4 . . . . from the ordered pair (2, 4)

  G(2) = 5 . . . .from the ordered pair (2, 5)

So your product is ...

  F(2)·G(2) = 4·5 = 20

  (F·G)(2) = 20

solution:

the given function is ,

      =

the three roots of this quadratic function is , 0 ,8 and 10.all the roots are real and rational.

if a quadratic equation is of the form ,

sum of the roots = a + b +c= 0+8+10=18=  

product of roots taken two at a time = a b + b c+ c a = 0+80+0=80 =  

product of roots = a b c = 0=  

there are 11 doors in a hall starting from 0 to 11.the entry in the hall is permitted through gate number 0 and exit is allowed through only gate number 8 and 10.so, three roots(0,8,10) of quadratic function is given by entry and exit route of this hall.