Find an exact value. tangent of seven pi divided by twelve

Tan
(
7
π
12
)
=
−
(
2
+
√
3
)
Explanation:
tan
(
7
π
12
)
=
tan
(
π
−
5
π
12
)
= #-tan((5pi)/12)
=
−
tan
(
3
π
12
+
2
π
12
)
=
−
tan
(
π
4
+
π
6
)
Now using
tan
(
A
+
B
)
=
tan
A
+
tan
B
1
−
tan
A
tan
B
=
−
tan
(
π
4
)
+
tan
(
π
6
)
1
−
tan
(
π
4
)
tan
(
π
6
)
=
−
1
+
1
√
3
1
−
1
×
1
√
3
Multiplying numerator and denominator by
√
3
=
−
√
3
+
1
√
3
−
1
=
−
(
√
3
+
1
)
2
(
√
3
−
1
)
(
√
3
+
1
)
=
−
3
+
1
+
2
√
3
3
−
1
=
−
(
2
+
√
3

Idon’t know i’m in the same boat