Solve the following question The difference of two numbers is 12 and their sum is 20 find the numbers

16 and 4

Step-by-step explanation:

Let (x+y) =20 and (x-y)=12 then:

Isolate for x in each equation

   x=20-y and x=12+y

Set the equations to equal each other since the value of x should be the same for both

   20-y = 12+y

Rearrange so that y is on one side and the numbers are on the other

   8 = 2y

   y= 8/2

   y= 4

Now  substitute the y- value back into either of the original equations

   x+y= 20

   x+4 = 20

Rearrange and isolate  x

   x = 20-4

   x = 16

So the two values are 16 and 4

dwe

step-by-step explanation:

ewd

the correct answer option is (2x-3)(2x+3).

step-by-step explanation:

we are given the following expression and we are to factorize it:

we are to find such factors that when multiplied they give a result of 36 (9 x 4 = 36) and when added they give a result of 0.

the two such factors of 36 are negative six and postive six.

factorizing the given expression to get:

therefore, the correct factorization of is (2x-3)(2x+3).