Solve for n: 21k − 3n + 9p > 3p + 12

n < 2p + 7k - 4

Step-by-step explanation:

Isolate the variable, n. Do the opposite of PEMDAS. Treat the > like an equal sign, what you do to one side, you do to the other.

First, subtract 21k and 9p from both sides:

21k (-21k) - 3n + 9p (-9p) > 3p (-9p) + 12 (-21k)

-3n > (3p - 9p) - 21k + 12

Simplify. Combine like terms:

-3n > (3p - 9p) - 21k + 12

-3n > (-6p) - 21k + 12

-3n > -6p - 21k + 12

Isolate the variable, n. Note that when you divide by -3, you divide from all terms, and you flip the sign:

(-3n)/-3 > (-6p - 21k + 12)/-3

n < (-6p - 21k + 12)/-3

n < (-6p)/-3 + (-21k)/-3 + (12/-3)

n < 2p + 7k - 4

n < 2p + 7k - 4 is your answer.

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step-by-step explanation:

∆abc has the points a(1, 7), b(-2, 2), and c(4, 2) as its vertices. formed with the point d(1, 2) as its third vertex, then ∆abd is triangle.

answer: no, but if it does it's a obvious pattern.

step-by-step explanation: