Plz help asap this table represent a quadratic function with a vertex a (1,2) what is the average rate of change for the interval from x=5 to x=6

9

Step-by-step explanation:

Given that (1, 2) is the vertex of the function represented by the table of values above, the rate of change for the interval from x = 5 to x = 6.

f(5) = 18

f(6) = ?

=>Find f(6) using the vertex form function, f(x) = a(x - h)² + k

Where, h and k are the given vertex of the function = (1, 2).

h = 1, k = 2

Thus,

f(x) = a(x - 1)² + 2

Find the value of a by using any of the points given in the table.

Using (3, 6), we have the following,

6 = a(3 - 1)² + 2

6 = a(2)² + 2

6 = 4a + 2

Subtract 2 from both sides

6 - 2 = 4a

4 = 4a

Divide both sides by 4

1 = a

a = 1

Let's find f(6) using f(x) = a(x - 1)² + 2

Plug the value of a and x

f(6) = 1(6 - 1)² + 2

f(6) = 25 + 2

f(6) = 27

==>Find the rate of change/slope

f(5) = 18

f(6) = 27

Rate of change =

Rate of change = 9

answer: sine

step-by-step explanation: