Two ants, Andy and Ashley, went to visit their friend. Andy crawled the whole way, but Ashley spent half of the way riding on a caterpillar, which was two times slower than crawling. Ashley spent the second half of the journey riding on a grasshopper, which was 5 times faster than crawling. Which ant got to their friend's house first, if they left at the same time?

Andy

Step-by-step explanation:

Let's say that x is Andy's speed, and d is the distance he traveled.

The time it takes Andy to reach his friend is d/x.

The time it takes Ashley to travel the first half is (d/2)/(x/2) = d/x.

The time it takes Ashley to travel the second half is (d/2)/(5x) = d/(10x).

The total time is d/x + d/(10x) = 1.1 d/x.

It takes Ashley 1.1 times longer to reach the friend.  Andy gets there first.

playboycarti! *

she tryna be crate.

d) by the cross product property, ab^2 = bc multiplied by ad

step-by-step explanation:

we are given

in the given triangle abc

angle a is 90° and segment ad is perpendicular to segment bc

we can see that

triangle(abc) and triangle(abd) are similar because they have common side and same angle (90 degree)

so, triangles(abc) and abd are similar

since, they are similar

so, the ratio of their sides must be equal

we get

now, we can cross multiply

and we get

so, this could be step to prove it