A researcher wishes to conduct a study of the color preferences of new car buyers. Suppose that 40% of this population prefers the color red. If 14 buyers are randomly selected, what is the probability that exactly 2 buyers would prefer red

The probability that exactly 2 buyers would prefer red car is 0.0317.

Step-by-step explanation:

Let the random variable X represent the number of buyers would prefer red car.

The probability of the random variable X is, p = 0.40.

A random sample of n = 14 buyers are selected.

The event of a buyer preferring a red car is independent of the other buyers.

The random variable X thus follows a Binomial distribution with parameters n = 14 and p = 0.40.

The probability mass function of X is:

Compute the  probability that exactly 2 buyers would prefer red car as follows:

Thus, the probability that exactly 2 buyers would prefer red car is 0.0317.

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hope this ! have a great day.

-wfz

the camry sales+accord sale=828,000. to make it so the two numbers are 18 thousand apart and still equal 828,000, you first need to find out what half of 828,000 is. 828,000/2=414,000. for the two numbers to equal 828,000, you have to add the same amount as you subtract from the middle. in this case, the number is 9,000 because it's half of 18,000. to equal 828,000, you have to add 9,000 to 414,000 for the camry and subtract 9,000 from 414,000 for the accord. 414,000+9,000=423,000.

414,000-9,000=405,000.

423,000+405,000=828,000.

423,000-405,000=18,

hope it