BRAINLIEST 6 points are placed on the line a 4 points are placed on the line b How many triangles is it possible to form such that their vertices will be the given points, if a is parallel to b?

all vertices on the two lines=60+36=96

Step-by-step explanation:

line a has 6 points and line b has 4 points

now each triangle drawn has on vertices on one line and two vertices on another line:

the line with six points :C(6,2) six points , has two vertices

C(6,2)=6*5/2*1=30/2=15 pairs of points

each pair connected to one point on the other line (4 points)

4*15=60 vertices

now let us consider the two lines on the other line with 4 points:

6c(4,2)=6*((4*3(/2))=6*6=36 vertices

all vertices on the two lines=60+36=96

ok so the answer to your question is simple as long as you look at the different dimensions that contain the exemplary letters that combined in the right order give you words that eventually within the 5th dimension will conform and give you the correct answer to your question. hope i , stop looking at this easily, look at it with a spectral view.

step-by-step explanation:

told you

no

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