Find the equation of the line with points (3,3) in y=mx+b where it is perpendicular to equation 5x+5-4y=0

y = -  x  +      or

5y = -4x + 27

Step-by-step explanation:

To find the equation of a line with points (3,3) and is perpendicular to   5x+5-4y=0

we will follow the steps below:

First find write the equation:  5x+5-4y=0  in standard form  y= mx + c and find the slope

5x+5-4y=0

4y = 5x + 5

divide through by 4

4y /4= 5x/4 + 5/4

y = x +  

comparing the above with y = mx + c

m=  

since the equations are perpendicular.

To find the new slope

 = -1

  = -1

multiply both-side of the equation by

×   = -1 ×

  =  -

The slope of our new  equation is  -

The points are (3,3)

We can now go ahead and form our new equation

y -  =  m ( x - )

y - 3 =  - ( x - 3)

y - 3 =  -  x  +  

y = -  x  + 3 +  

y = -  x  +

5y = -4x + 27

y = x + 95

y = 42 + 95

y=137 mm hg