Please solve for x and y. If you do, also write the steps you used.

a = 8, x = 56, y = 68

Step-by-step explanation:

Was there a description that stated this was a parallelogram?

Since that information was not provided....

I used the Law of Cosines to find x = 56°.

Congruent sides implies congruent angles so Center-Q-R = 56°.

Triangle Sum Theorem results in y = 68°

Vertical angles results in S-Center-P = 68°

Triangle sum Theorem results in S-P-Center = 68°

Now we can see that alternate interior angles are congruent, therefore PQRS is a parallelogram. Diagonals are bisected at the intersection so a = 8

question is incomplete.

g(x) = 3*(8(3^(x−2))+2)

g(x) = 24 (3^(x-2) )+6

the factor is 2

step-by-step explanation:

let f(x)=8(3^(x−2)+2)

to stretch a graph by 3, it would be 3f(x)

g(x) =3f(x)

g(x) = 3*(8(3^(x−2))+2)

g(x) = 24 (3^(x-2) )+6

x     −2     0     2     4     6

f(x) 1/64 1/16   1/4     1     4

1/64 * z * z = 1/16

i multiplies by z twice because it its 2 steps from -2 to 0

1/64 z^2 = 1/16

multiply by 64 to clear the fraction on the left side

1/4 * 64 z^2 =1/16 *64

z^2 = 4

take the square root of each side

sqrt(z^2) = ±sqrt(4)

z = ±2  

we are multiplying by 2 each time.