Arun is twice as old as Shreet 5 years ago his age was three times shree age find their present ages

 Arun is now 20, Shree is 10 years old

Step-by-step explanation:  

In the system of equations Arun's age is a. Shree is s

a = 2s .(current age equation)  Subtract 5 from each for five years ago,

a-5 = 3(s-5) . Substitute 2s for a in the second equation

2s -5 = 3(s-5)  distribute and reorganize

2s-5 = 3s -15 .   15 - 5 = 3s - 2s

10 = s .  Substitute into the first equation to find a

a = 2(10)

a = 20

5 years ago  Shree was 5 and Arun was 15

Arun = 20, Shreet = 10

Step-by-step explanation:

Let A represent Arun's current age and S represent Shreet's current age

             Current Age               Age 5 years ago

                A = 2S                         A - 5 = 3(S - 5)

Substitute A = 2S into the "5 years ago" equation to solve for S:

(2S) - 5 = 3(S - 5)

2S - 5 = 3S - 15

      -5 =  S - 15

     10 = S

Substitute S = 10 into the "current age" equation to solve for A:

A = 2S

  = 2(10)

  = 20

  q

step-by-step explanation:

each line from a vertex to the midpoint of the opposite side is called a median. the point where the medians intersect, point q, is the centroid.

the centroid of δabc is point q.

c. y = 1/4 x + 5

step-by-step explanation:

first, put the equation of the line on the graph into slope-intercept form

(y = mx + b):   y = -4x + 8

second, a perpendicular line has to have "an opposite/reciprocal slope" to the original slope. so, find the "m" value in your original equation (it's -4, right? )

original slope: m = -4   perpendicular slope: change the sign to its opposite and find the reciprocal ("flip" the number)

new slope is now positive (b/c the original slope was negative 4), and it's 1/4 (not the original slope of 4 or 4/1)