3/4, 1, 4/3, 16/9,... which of the following are recursive formulas for the nth term of the following geometric sequence?

nth term of geometric sequence = a(n) =

Step-by-step explanation:

nth term of geometric sequence = a(n)

nth term of geometric sequence = a(n) =

Where,

a =  first term

r = common ratio

n = number of term

So,

GP: 3/4, 1, 4/3, 16/9

a = 3/4

r = 1 / [3/4] = 4/3

n = n

nth term of geometric sequence = a(n) =

nth term of geometric sequence = a(n) =

x equals 1

step-by-step explanation:

f(4)=f(×)

x=1

8+10

step-by-step explanation:

you multiply 4 by 2 and 5 by 2