Any fake answers will get reported but if u do good u get brainliest:) - Fred's coffee shop sells two blends of beans at the following prices. a) House Blend ($3.50/lb) b) Exotic Blend ($4.00/lb). House blend is 1/2 Costa Rican beans and 1/2 Ethiopian beans. Exotic blend is 1/4 Costa Rican beans and 3/4 Ethiopian beans. Every day Fred receives 200 lbs of Costa Rican Beans and 330 lbs of Ethiopian beans. What are the common sense constraints? - - x or = 530 - x > or = 0, and y > or = 0

Since he needs beans to sell. The common sense constraints would be that both x and y need to be equal to or greater than 0, otherwise he wouldn’t have anything to sell.

The answer is the last choice

x>=0, and

y>=0

Step-by-step explanation:

Let

x = pounds of house blend he sells/makes every day

y = pounds of exoted blend he makes/sells every day

constraint for costa rican beans

x/2 + y/4 <= 200 (1)

constraint for Ethiopian beans

x/2 + 3y/4 <=330(2)

Total weight per day

x+y <= 200+330 = 530(3)

common sense constraints, cannot have negative weight for coffee

x>=0, and

y>=0

no solution

step-by-step explanation:

there is not enough information in the problem to solve.

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step-by-step explanation: