The half-life of iron-52 is approximately 8.3 hours. Step 1 of 3: Determine a so that A(t)=A0at describes the amount of iron-52 left after t hours, where A0 is the amount at time t=0. Round to six decimal places.

Step-by-step explanation:

Given the half like of a material to be 8.3 hours and the amount of iron-52 left after t hours is modeled by the equation , we can get A(t) as shown;

At t = 8.3 hours, A(8.3) = 1/2

Initially at t = 0; A(0) = 1

Substituting this values into the function we will have;

step-by-step explanation:

sry but any answer choices

35 is an outlier

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