60 POINTS Part A: Identify a pair of similar triangles. Part B: Explain how you know the triangles from Part A are similar. Part C: Find the distance from B to E and from P to E. Show your work.

Step-by-step explanation:

Part (A).

ΔGBC and ΔEBP will be the similar triangles.

Part (B).

Since GC║ER and PC is a transverse,

∠EPB ≅ ∠GCB [Alternate angles]

Similarly, GC║ER and GE is the transverse,

∠CGB ≅ ∠PEB [Alternate angles]

By AA postulate of similarity, ΔGBC ~ ΔEBP.

Part (C).

Since ΔGBC ~ ΔEBP, their corresponding sides will be proportional.

Therefore,

BE =

BE = 294.23 units

Similarly,

PE =

PE = 259.62 units