A chemical company mixes pure water with their premium antifreeze solution to create an inexpensive antifreeze mixture. The premium antifreeze solution contains pure antifreeze. The company wants to obtain gallons of a mixture that contains pure antifreeze. How many gallons of water and how many gallons of the premium antifreeze solution must be mixed

Water: 120 gallons

Premium Antifreeze: 200 gallons

Step-by-step explanation:

Had to complete the question first.

A chemical company mixes pure water with their premium antifreeze solution to create an inexpensive antifreeze mixture. The premium antifreeze solution contains 80% pure antifreeze. The company wants to obtain 320 gallons of a mixture that contains 5% pure antifreeze. How many gallons of water and how many gallons of the premium antifreeze solution must be mixed?

Water: gallons

Premium Antifreeze: gallons

Solution:

Let w = amt of water required

An equation based on the the percent water, an 80% solution is 20% water

Multiply through

= 20% (320 - w) + w = 50% x ( 320)

64 - 0.2w + w = 160

Collecting like times

0.8w = 160 - 64

w = 96%

w = 120 gal of water to produce 320 gal of 50% antifreeze

320 - 120 = 200 gal of 80% solution

Water: 120 gallons

Premium Antifreeze: 200 gallons

d. it is a convex pentagon because it has five sides and none of the sides would extend into the inside of the polygon.

step-by-step explanation: