A television station claims that the amount of advertising per hour of broadcast time has an average of 16 minutes and a standard deviation equal to 1.4 minutes. You watch the station for 1 hour, at a randomly selected time, and carefully observe that the amount of advertising time is equal to 8 minutes. Calculate the z-score for this amount of advertising time. Group of answer choices

-4.29

Step-by-step explanation:

The computation of the z score is shown below:

data provided in the question

Average minutes = 16 minutes

Standard deviation = 1.4 minutes

Amount of advertising time = 8 minutes

Based on the above information, the z score is

= -4.29

Hence, the z score is -4.29. It is come by considering the above formula

i think it is c, not positive though

step-by-step explanation:

whole numbers.

step-by-step explanation:

we are given the average monthly rainfall (in millimeters) model r(m) for the years 1900-2009 as a function of the month number m.

as we can see m is taken for the number of months for years 1900-2009.

we know that number of months can't be a negative number or decimal number or a fraction.

so, the number of months could be only positive whole numbers.

therefore, whole numbers is more appropriate for the domain of r.