At what point on the curve y = 2 + 2ex − 4x is the tangent line parallel to the line 4x − y = 3? (x, y) =

{ln 4, (2 + 2e^ln 4 − 4 ln 4)} or (1.39, 4.45)

Step-by-step explanation:

From this equation 4x − y = 3

-y = 3 - 4x

then, y = 4x - 3

From line equation y = mx + b

Therefore, the slope is 4

Since the are parallel line, they will have same slope

Finding the derivative of y = 2 + 2e^x − 4x

y = 2 + 2e^x − 4x

y' = 0 + 2e^x - 4

Therefore,

4 = 2e^x - 4

4 = e^x

x = ln 4 = 1.39

To find the y coordinate

y = 2 + 2e^x − 4x

y = 2 + 2e^ln 4 − 4 ln 4

y = 4.45

Hence, they are parallel at point (1.39 and 4.45)

hi there!

the answer to this question is d: 35

step-by-step explanation:

5 to the power of 2 is 25

2 multiplied by 5 is 10

then you add the 2 numbers and you get 35

n=9

step-by-step explanation:

7 times a number = 7n

decreased by 13 = 7n-13

same as is =

5 times the number = 5n

increased by 5 = 5n+5

7n-13 = 5n+5

2n=18

n=9