The two square pyramids are similar. The side length of the smaller pyramid is the side length of the larger pyramid. Which fraction represents the ratio of the base area of the smaller pyramid to the base area of the larger pyramid?

9/16

see explanation below

Step-by-step explanation:

This question is lacking figures. But it is easy to solve question asking for the ratio of the areas of a shape when the shapes are similar.

When shapes are similar, the ratio of their corresponding sides are equal.

whilst the ratio of the area of similar shapes is equal to the square of the ratio of their corresponding sides.

In other words, if the corresponding sides are a and b respectively, the ratio of their sides = a/b

and the ratio of the areas of the shape = (a/b)²

Assumption: Now if the side length of the smaller pyramid is 3/4(the side length of the larger pyramid)

let length larger pyramid = x

length of smaller pyramid = 3/4 x

their ratio (small/big) = (3x/4)/x = 3/4

ratio of their areas = (3/4)²

the ratio of base area of the smaller pyramid to the base area of the larger pyramid = 9/16

intensity of the vector is v= √37 ≈ 6.08 units and make angle ∡α ≈ 9.46° with east direction

step-by-step explanation:

required vector is consists of the two componentsvx= 2+4=6 units   and vy= 1 unit and vx ⊥ vywe will use pythagorian theorem to find intensity of the vector vv∧2 = vx∧2 + vy∧2 => v = √vx∧2 + vy∧2 = √6∧2 + 1∧2 = √36+1 = √37 ≈ 6.08 unitsthe angle ∡α between vector and east direction we wil find with tanαtanα = 1/6 => α = arc tanα = arc 1/6 => α ≈ 9.46°

hope this

the answer is 375 miles

step-by-step explanation: