Solve the system of equations. {y=30x+10y=5x2−25 Enter your answers in the boxes.

Step-by-step explanation:

Given the system of equations y=30x+10 y=and 5x²−25, since both functions are written in terms of  a varaible y, we will equate the two functions to gether and firt alculate the value of x as shown;

30x+10 =  5x²−25,

Equating the expression to zero;

5x²−25-30x-10 = 0

5x²−30x-25-10 = 0

5x²−30x-35 = 0

Dividing through by 5;

x²−6x+7 = 0,

On factoring;

x = -b±√b²-4ac/2a

a = 1, b = -6 and c = 7

x = 6±√(-6)²-4(1)(7)/2(1)

x = 6±√36-28/2

x = 6±√8/2

x = 6±2√2/2

x = 3±√2

x = 3+√2 or 3-√2

Substituting x = 3+√2 into y = 30x+10

y = 30(3+√2 ) + 10

y = 10(3(3+√2)+1)

y = 10(9+1+3√2)

y = 10(10+3√2)

(53.5 - 18.4) m.

step-by-step explanation:

after undergoing a displacement of 18.4m, the initial position was (53.5 - 18.4) m if an object has a final position of 53.5.