determine the equation of the line perpendicular to y=5/2x+6/5 with the same x-interpret as the line defined by 3x+8y-15=0

y = -2/5x+2

Step-by-step explanation:

The slope of the line perpendicular to the given line is the negative reciprocal of the slope of the given line. i.e, slope of the perpendicular line is -2/5

the x- intercept of 3x+8y-15=0 is determined by substituting zero for the value of y in the equation

3x + 8 *(0) -15 =0

3x-15 = 0

3x =15

x= 5

so, the point we need to find the equation of the line perpendicular to the equation y=5/2x + 6/5 is  (5,0)

we consider the slope-intercept equation

y = mx + b

0 = - 2/5 *(5) + b

0 = - 2 + b

b= 2

so, our equation is y = -2/5x+2

17   x 256=4352

sorry if this is wrong, i'm new.

step-by-step explanation:

the answer to question 1 is -8, 28.

step-by-step explanation: