PLEASE HELP! What is the length of the shortest altitude in a triangle, if the lengths of the sides are 15 cm, 17 cm, 8 cm. NO DECIMALS

The shortest altitude = 8 cm

Step-by-step explanation:

Where we have the sides given by

15 cm, 17 cm, 8 cm

From cosine rule, we have;

a² = b² + c² - 2×b×c×cos(A)

We have

For the side 15 cm,

15² = 17² + 8² - 2×17×8 cos A

-388 = -612×cos×A

A = 61.93°

17² = 15² + 8² - 2×15×8 ×cos B

0 = -240·cos B

B = 90°

Therefore, 17 is the hypotenuse side and 15 and 8 are the legs, either of which can be the height which gives the shortest altitude as 8 cm

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