Drag each factor to the correct location on the image. If p(1) = 3, p(-4) = 8, p(5) = 0, p(7) = 9, p(-10) = 1, and p(-12) = 0, determine which expressions are factors of the polynomial p(x).

Factor: x-5 & x+12

Not a Factor: x-1, x+4, x-7, x+10

Step-by-step explanation:

The remainder theorem states that for a polynomial p(x) and a number a, the remainder on division of p(x) by x − a is p(a). So, p(a) = 0 if and only if x − a is a factor of p(x).

Since, p(5) = 0 and p(-12) = 0, the expressions (x − 5) and (x + 12) are factors of the polynomial p(x).

5=812a+9+3

step 1: simplify both sides of the equation.

5=812a+9+3

5=(812a)+(9+3)(combine like terms)

5=812a+12

5=812a+12

step 2: flip the equation.

812a+12=5

step 3: subtract 12 from both sides.

812a+12−12=5−12

812a=−7

step 4: divide both sides by 812.

812a /812 = -7/812

a= -1/116

so the answer is

a=   -1/116