IMAGE BELOW The equations x minus 2 y = 4, 4 x + 5 y = 8, 6 x minus 5 y = 15, and x + 2 y = 0 are shown on the graph below. Which system of equations has a solution of approximately (1.8, –0.9)?
6 x minus 5 y = 15 and x + 2 y = 0
4 x + 5 y = 8 and 6 x minus 5 y = 15
x minus 2 y = 4 and 4 x + 5 y = 8
6 x minus 5 y = 15 and x minus 2 y = 4

6x - 5y = 15 and x + 2y = 0

Step-by-step explanation:

Here we are given the following equations:

i) x-2y= 4

ii) 4x+5y= 8

iii) 6x-5y=15

iv) x+2y=0

Required:

Which system of equations has a solution of approximately (1.8, –0.9).

To find the approximate equations, substitute x and y for  1.8 and  -0.9 into all the equations respectively and check the resulting values

i) Substitute (1.8, -0.9) in x-2y= 4:

1.8 - 2(-0.9) = 4.

1.8 + 1.8 = 4.

3.6 ≠ 4.

ii) Substitute (1.8, -0.9) in 4x+5y= 8

4(1.8) + 5(-0.9) = 8

7.2 - 4.5 = 8.

2.7 ≠ 8.

iii) Substitute (1.8, -0.9) in 6x-5y=15

6(1.8) - 5(-0.9) = 15.

10.8 + 4.5 = 15

15.3 ≠ 15.

This equation has a solution that is close, therefore it is correct.

iv) Substitute (1.8, -0.9) in x+2y=0

1.8 + 2(-0.9) = 0.

1.8 - 1.8 = 0.

0 = 0.

x + 2 y = 0 has the exact value, therefore it is also correct.

The system of equations that has a solution of approximately (1.8, –0.9) are:

x+2y=0 and 6x-5y=15

1

step-by-step explanation:

it's the only multiple of both and the least

where's the diagram?

step-by-step explanation: