A student wants to determine if there is a difference in the pricing between two stores for health and beauty supplies. She recorded prices from both stores for each of 10 different products. Assuming that the conditions for conducting the test are satisfied, determine if there is a price difference between the two stores. Use the alphaequals0.1 level of significance. Complete parts (a) through (d) below. A B C D E F G H I J Store 1 5.94 7.47 3.79 1.74 1.73 2.88 4.75 3.15 2.92 3.77 Store 2 5.96 7.97 3.97 1.72 1.96 2.49 4.74 3.75 2.99 3.61

There is no price difference between the two stores.

Step-by-step explanation:

The dependent t-test (also known as the paired t-test or paired samples t-test) compares the two means associated groups to conclude if there is a statistically significant difference amid these two means.

In this case a paired t-test is used to determine if there is a price difference between the two stores.

The hypothesis for the test can be defined as follows:

H₀: There is no price difference between the two stores, i.e. d = 0.

Hₐ: There is a price difference between the two stores, i.e. d ≠ 0.

From the information provided the sample mean and standard deviation are:

Compute the test statistic value as follows:

The test statistic value is -1.44.

Decision rule:

If the p-value of the test is less than the significance level then the null hypothesis will be rejected and vice-versa.

The degrees of freedom is:

n - 1 = 10 - 1 = 9

Compute the p-value of the test as follows:

*Use a t-table.

The p-value of the test is 0.184.

p-value= 0.184 > α = 0.10

The null hypothesis was failed to be rejected.

Thus, it can be concluded that there is no price difference between the two stores.

  b.   the average rate of change of f(x) is less than the average rate of change of g(x).

step-by-step explanation:

since the length of the interval is the same in each case, we only need to compare the change in y-value to see which is greater.

so the change in y-value for function f is (6 )) = 9.

the table tells us

so the change in y-value for function g is (31 -1) = 30.

the change in y-value of f(x) on the interval is less than the change in y-value of g(x) on the same interval, so the average rate of change of f(x) is less than the average rate of change of g(x).

answer: 230 miles ( vote ! )

step-by-step explanation:

180.39 minus 17.99 equals 162.4

then divide 162.4 by .80 to get 230