Explain how to do this question plz

about 17.7%

Step-by-step explanation:

The area of a trapezoid is ((b1+b2)/2)*h

Thus, the area of the trapezoid is 85 meters squared.  Thus, because the garden is 480 meters squared, the trapezoid occupies 85/480 of the garden, or about 17.7 percent.

Hope it helps <3

17.7% rounded to the nearest tenth

Step-by-step explanation:

Well to find the percent of space the trapezoid takes up we need to find both areas.

To find the area of a Rectangle we do l*w.

So the l is 30 and the w is 16 so,

30*15 = 480m^2

To find the area of a Trapezoid .

So b1 is 20 and b2 is 14,

14 + 20 = 34

34/2 = 17

17 * h

17 * (5) = 85m^2

So now we make a fraction of the areas of the trapezoid and rectangle,

Now we simplify,

85/5 = 17

480/5 = 96

So 17/96 is in its simplest form so now we do 17/96 which is 0.1770833333

So to the following into a percent we move the decimal places 2 places to the right which is about 17.7% rounded to the nearest tenth.

tell you what. i'll find the length of the medians and you can fill in the blanks where they belong.

br

b = (2a,0)

r = (a/2,b/2) remember these things are medians. they go to the 1/2 way point of the line opposite the vertex they face.

br^2 =   (2a - a/2)^2 + (0 - b/2)^2

br^2 = (3/2 a) ^2 + b^2 / 4

br^2 = 9/4 a^2 + b^2 / 4   we need to find some relationship between a and b.

let's try ab = bc  

ab = 2a

bc = (2a - a)^2 + (b - 0)^2

bc = sqrt(a^2 + b^2)

ab = bc

2a = sqrt(a^2 + b^2) square both sides.

4a^2 = a^2 + b^2 subtract a^2 from both sides.

sqrt(3a^2) = sqrt(b^2)

sqrt(3)a = b

let's put b into br^2

br^2 = 9/4 a^2 + 3b^2 / 4

br^2 = 12 a^2 / 4

br^2 = 3a^2 

br = sqrt(3) * a

cp

c = (a,b) ; p = (a,0) this is another application of the distance formula, and it is a good one.

cp^2 = (a - a)^2 + (b - 0)^2

cp^2 = 0 + b^2

cp^2 = b^2 which you can see from the diagram. 

cp = sqrt(b^2)

cp = b but b = sqrt(3) * a 

cp = sqrt(3)*a

aq

a = (0,0)

q = (3/2) a, b/2

aq^2 = (3a/2 -0)^2 + (b/2 - 0)^2

aq^2 = 9a^2/4 + b^2/4

but b = sqrt(3) * a 

aq^2 = 9a^2 / 4 + (sqrt(3)*a)^2 /4

aq^2 = 9 a^2/ 4 + 3 a^2 / 4

aq^2 = 12 a^2/4

aq^2 = 3 a^2

aq = (sqrt  3) * a which agrees with the other two.

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