According to the Insurance Institute of America, a family of four spends between $400 and $3,800 per year on all types of insurance. Suppose the money spent is uniformly distributed between these amounts. If we select a family at random, what is the probability they spend less than $2,000 per year on insurance per year? (Round your answer to 4 decimal places.)

0.471

Step-by-step explanation:

Calculation for the probability that they spend less than $2,000 per year on insurance per year

First step is to find the base

Base =$2,000-$400

=$1,600

Second step is to find the probability using this formula

P=1/b+a×base

Where,

b represents $3,800

a represents $400

base represents $1,600

Let plug in the formula

P=1/$3,800-$400×$1,600

Hence,

P=1×$1,600/$3,800-$400

P=$1,600/$3,400

P=0.471

Therefore the probability that they spend less than $2,000 per year on insurance per year will be 0.471

step-by-step explanation:

12: 00 p.m. to 7: 00 p.m. is a total of 7 hours.

4: 00 p.m. to 7: 00 p.m. is a total of 3 hours.

this means that from 4: 00 p.m to 7: 00 p.m. this represents 3/7 of what was lost from 12: 00 p.m. to 7: 00 p.m.

after knowing this, after doing 11,600 - 6,800 = 4,800

4,800 represents 3/7 of what was lost for 7 hours.

we then divide 4,800 by 3 which gets 1,600.

because we know that 1,600 represents 1/7 of how much water was lost, we just have to multiply by 7, which gets 11,200.   after adding 11,200 to how much water was left at 7: 00 p.m. which was 6,800. 11,200 + 6,800 = 18,000

this means that the pool originally had 18,000 gallons in the pool.

you can also check your work by doing 18,000 - 4(1600), which becomes           1800 - 6400 which gets you 11,600.

i believe the answer is 323 ft

step-by-step explanation: