Verify the identity below with work and/ or explanation. 2gh/sin^2θ = 2gh sec^2θ/sec^2θ-1 Thanks!

identify is verified, see work below.

Step-by-step explanation:

Verify following identity

2gh/sin^2θ = 2gh sec^2θ/sec^2θ-1

use identity 1+tan^2(θ) = sec^2(θ) on denominator of right-hand-side

right-hand side

= 2gh sec^2(θ) / (sec^2(θ)-1)

=  2gh sec^2(θ) / (tan^2(θ))

=  2gh sec^2(θ) * (cos^2(θ) / sin^2(θ) )   [note: sec^2(θ) = 1/cos^2(θ)]

= 2gh * 1 / sin^2(θ)

= 2gh / sin^2(θ)

= left-hand side

Therefore identify is verified.

spinning a 1, 2, or 3. option d.

step-by-step explanation: when spinning a number graph up to 4, and aiming for any number less than 3, that automatically eliminates the number 4. now you have two numbers to spin on that are less than 3, but the number 3 is included in this question because it's no greater of an number than itself. i hope this you : )

answer: group b.

step-by-step explanation: