Written in simplest form, the expression (x^2)(y^2)-9 over 3-xy is equivalent to
1. -1
2. 1 over 3+xy
3. -(3+xy)
4. 3+xy
show work

((x^2)(y^2) - 9) *(3 - xy).

Note difference of two squares:  (a^2 - b^2) = (a-b)(a+b)
(x^2)(y^2) - 9 = (xy)^2  - 3 ^2 = (xy - 3)(xy + 3).    (Take note)

(3- xy) = -(xy - 3).    (Take note of this also)

Your question said:  ((x^2)(y^2) - 9) times (3 - xy),
Don't you think it should be divide? Would solve it as divide.

((x^2)(y^2) - 9) /(3 - xy)  =  (xy - 3)(xy + 3) / -(xy - 3)

                                  =  -(xy + 3).

Answer is (3). Solved it as divide. Using times gives none of the solution among the options.
Cheers.

than do 23.50 times 18 and then divide your answer by 100 than you will get x.