PLSSS HELP!! I'LL GIVE BRAINLIEST IF RIGHT Which is the equation of a parabola with a directrix at y = 2 and a focus at (5, 0). A) y = one fourth(x − 5)2 + 1 B) y = one fourth(x + 1)2 − 5 C) y = −one fourth(x + 1)2 − 5 d) y = −one fourth(x − 5)2 + 1

First, we need to set up a (y−k)^2=4p(x−h). After plugging in all of your values, you would get (x-5)^2=-4(y-1). Now, we need to solve in terms of y by dividing each side by the factors that don't contain the variable

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for the points

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answer: c

step-by-step explanation: because you don't have to draw a point of intersection. couldyou give me brainliest?

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