A group of individuals containingbboys andggirls is lined up in random order;that is, each of the (b+g)! permutations is assumed equally likely. What is theprobability that the person in theith position, 1≤i≤b+g, is a girl?

g/(b+ g)

Step-by-step explanation:

I have attached the solution below.

step-by-step explanation:

always plug in x. in this case, x equals 4.

i'm going to first solve 4(2+3x)

1) 4(2+3(4)) use pemdas to solve.

i'm going to multiply whats in the parenthesis first, so 3 times 4=12.

2)4 (2+12) i'm then going to multiply 4 by both numbers in the parenthesis (because multiplying comes before adding)

4 times 2= 8.   4 times 12= 48

4) (8+48)= 56 (answer)

i'm then going to solve 8+12x and plug in 4 for x.

1) 8 +12(4)

multiplying comes before adding, so i'm gonna multiply 12 and 4.

12 times 4= 48.

2) 8+48=56

both equal the same!

good job you smart son of a gun you are smarter that einstein. 7