John and will also ran for Middle School council president. There are 90 students voting in middle school. If the ratio of Will's votes to John's votes are the same how many vo

Hi!

This problem is the fifth in a series of seven about ratios. At first glance the problem may look to be beyond 6.RP.1, which limits itself to “describe a ratio relationship between two quantities. However, even though there are three quantities (the number of each candidates' votes), they are only considered two at a time.

In the first problem students define the simple ratios that exist among the three candidates. It opens an opportunity to introduce unit rates.

The subsequent problems are more complex. In the second problem, students apply their understanding of ratios to combine two pools of voters to determine a new ratio. In the third problem, students apply a known ratio to a new, larger pool of voters to determine the number of votes that would be garnered.

Solutions

Solution: Question #1

a. John's votes to Will's, 16 to 8, or 2 to 1. Marie's votes to Will's, 12 to 8, 3 to 2, or 32 to 1, the unit ratio. Marie's votes to John's, 12 to 16, 3 to 4, or 34 to 1, the unit ratio.

Solution: Question #2

2. Will now has 8 + 12 = 20 votes to John's 16 votes, so the ratio of Will's votes to John's votes is 20 : 16, 5 : 4, or 54 : 1, the unit ratio.

Solution: Question #3 - Computing votes

There are different ways to approach this problem, but both begin with the fact that Will gets votes in a 5 to 4 ratio compared with John and require recognizing that a 5 to 4 ratio means a total of 9 equal parts. Then it is straightforward to compute:

59×90=50 votes for Will

49×90=40 for John

50−40=10 more votes for Will.

Solution: Question #3 - Applying fractions

One can solve the problem by working fractions by recognizing that Will getting votes in a 5 to 4 ratio means a total of 9 equal parts. It follows that Will gets 59 of the 90 votes and John gets 49 of the 90 votes:

59−49=19 of the voters

19×90=10 more votes for Will

Solution: Question #3 - Equivalent Ratios

An alternate very basic solution to Question 3 involves creating a series of equivalent ratios. This approach may be selected by students who are still developing an understanding of proportional situations. Students may begin with the ratio of 5 to 4 and proceed to find a ratio such that the sum of numerator and denominator is 90. This sequence may appear as follows:

5/4 = 10/8 = 15/12 = 20/16 = 25/20 = 30/24 = 35/28 = 40/32 = 45/36 =50/40

Then 50 - 40 = 10 more votes for Will

Overall answer

10 more votes for will

let x be the money she spent so that she can earn the free t-shirt.

since, she already spent $112.49

⇒

also, as per the statement: jennifer must spend $250 or more in order to qualify for a free t-shirt at the store.

then,

we have an inequality i.,e

subtract 112.49 from both sides we get;

therefore, $137. 51 more money does jennifer need to spend so that she can earn the free t-shirt

well we know there are 4 clubs in 52 cards so it’s replaced so it should be 3/51

step-by-step explanation: