Two cylinders have the same volume. For the first cylinder, the radius of the base is 20 inches and the height is 11 inches. The second cylinder has a radius of 8 inches. What is the height of the second cylinder rounded to the nearest hundredth?

68.75 inches

Step-by-step explanation:

piR^2H is the equarion for the bolume of a cylinder.

20/2 is 10. pi(20^2)11

which is 13823.01

So now it will be 13823.01=pi(8^2)(x)

Divide out pi

4400 = (8^2)(x)

Divide out 8^2 which is 64

68.75=x

4 and 5)16.97 or 12√2

6)15.59 or 9√3

7)y = 15.59 or 9√3     x =27

8)17.80

answer: 40392

step-by-step explanation:

10098 x 4 = 40392