Consider the following intermediate chemical equations. (9)+201(9) — COCO
CO(g)+202(9) — 00,0
How will oxygen appear in the final chemical equation?
O2(g) as a product
O2(g) as a reactant
O O(g) as a product
20(g) as a reactant

see explanation

step-by-step explanation:

a

(6r + 7) + (13 + 7r) ( remove brackets and collect like terms )

= 6r + 7 + 13 + 7r

= 13r + 20

b

remove brackets and collect like terms

13 - r - 1 + r

= 12 - r

c

remove brackets and collect like terms

= - 8 - r + 2r - 4

= - 12 + r

d

remove brackets and collect like terms

= 7r - - - 6r

[-   - = - - = - ]

= r -

answer: 8

step-by-step explanation: if you add the possibilities 5 different flavor and 3 different sizes 5+3=8

it has to have an angle of 90 degrees