A rectangle is 1 inch longer than it is wide. Its diagonal is 5 inches. What's the width of the rectangle?

The width is 4 inches

Step-by-step explanation:

Represent the length and width by L and W respectively.  Then L = W + 1.

According to the Pythagorean Theorem, the diagonal length is

D = sqrt( [W]^2 + [W + 1}^2 ) = 5, or [W]^2 + [W + 1}^2 = 25.

Then W^2 + W^2 + 2W + 1 = 25, and 2W^2 + 2W - 24 = 0.

Reducing, we get W^2 + W - 12 = 0, or (W + 4)(W - 4) = 0.  Then W - 4 = 0, and W (the width) is 4.  Then L = 5.

The width is 4 inches.

can someone answer this question plz

step-by-step explanation:

x= -3 and

step-by-step explanation:

to find the roots of a cubic, use division or factoring to find the factors then set equal to 0. as this is a difference of cubes, it factors into

where a is the cube root of .

here   this is 27 and the cube root of 27 is 3. so we write using the form:

.

set each factor to 0 and solve for x.

x-3=0

x=3

the quadratic expression does not factor and must be solved using the quadratic formula.

where a = 1, b=3, and c=9

this cubic has two complex roots.