A jet flies 425 km from Ottawa to Québec at rate v + 60. On the return flight, the plane encountered wind resistance and travelled at rate v - 40. What is the
difference in flight times of the initial and return flights?

a.

Step-by-step Explanation:

Given:

Distance Ottawa to Québec = 425 km

Initial flight rate = v + 60

Return flight rate = v - 40

Required:

Flight times difference of the initial and return flights

Solution:

=>Flight time of the initial flight:

=>Flight time of the return flight:

=>Difference in flight times:

-7/8

step-by-step explanation:

instead of subtracting you add the -6/8 and -1/8