One number is 6 more than another. Their product is -9. Need help fast

the numbers are 3 and -3

Step-by-step explanation:

let the unknown number be x

The first UNKNOWN NUMBER = X

The second unknown number is = 6 + x

Their product = -9

(X)(6 + X) = -9

6x +=-9

+6x +9=0

we multiply the coefficient of x which is 1 with 9

now, we look for two numbers that when multiplied will give us 9 and when added will give 6 and that is 3 and 3

+3x+3x +9 = 0

x(x+3) +3(x+3) = 0

(x +3 ) = 0

or (x +3)=0

x +3 =0

x=0 -3

x =-3

x +3=0

x =0-3

x =-3

since the numbers are the same ,we pick one

therefore,the first number =x =-3

the second number is 6 + x=6 + (-3)

6-3=3

"image"

step-by-step explanation:

in most of these problems, the notation is that the point with a "prime" is the image of the point without. that is, b' is the image of b.

here, there is no dilation or reflection. there is simply translation (with no direction shown). which figure you call the "preimage" and which one you call the "image" is up to you. as a matter of convention, the naming is as described above.