Example 2 A black die and a white die are thrown at the same
time. Display all the possible outcomes. Find the
probability of obtaining:
a) a total of 5
b) a total of 11
c) a 'two' on the black die and a six' on the white die.
It is convenient to display all the possible outcomes
on a grid. This is called a possibility diagram

It’s example 2 please help:)

Total possible outcomes = 6×6 = 36

a) P(5) = 1/9

b) P(11) = 1/18

c) P(two and six) = 1/36

Step-by-step explanation:

A black die and a white die are thrown at the same  time.

Each die has six sides so total possible outcomes are

Total possible outcomes = 6×6 = 36

The possible outcomes are given below:

(1, 1)  (1, 2) (1, 3) (1, 4) (1, 5) (1, 6)

(2, 1) (2, 2) (2, 3) (2, 4) (2, 5) (2, 6)

(3, 1) (3, 2) (3, 3) (3, 4) (3, 5) (3, 6)

(4, 1) (4, 2) (4, 3) (4, 4) (4, 5) (4, 6)

(5, 1) (5, 2) (5, 3) (5, 4) (5, 5) (5, 6)

(6, 1) (6, 2) (6, 3) (6, 4) (6, 5) (6, 6)

a) Find the  probability of obtaining a total of 5

Number of ways to get a total of 5 = (1, 4) (2, 3) (3, 2) (4, 1)

Number of ways to get a total of 5 = 4

The probability is given by

P = Number of desired outcomes/total number of outcomes

P(5) = 4/36

P(5) = 1/9

b) Find the  probability of obtaining a total of 11

Number of ways to get a total of 11 = (5, 6) (6, 5)

Number of ways to get a total of 11 = 2

The probability is given by

P(11) = 2/36

P(11) = 1/18

c) a 'two' on the black die and a six' on the white die.

There is only one way to get a two on the black die.

Probability of obtaining a two on the black die = 1/6

There is only one way to get a six on the white die.

Probability of obtaining a six on the white die = 1/6

P(two and six) = 1/6×1/6

P(two and six) = 1/36

47.28 or 47.2857143

step-by-step explanation:

you just divide 331 by 7 and you get that answer. ( i think so tho)