The distance between two cities A and B is 400km. A car leaves from A towards B at a speed of 90kmph, at the same time another car leaves from B towards A at 110kmph. -
a) Write the equations that give the distance as function of time.
b) Represent them graphically. V
c) Find the distance they have traveled to meet each other and the time invested.

a. Distance = 400 - 200t

b. see attached graph

c. A travelled 180 km, B travelled 220 km, both took 2 hours.

Step-by-step explanation:

Given

distance = 400

A = 90 km/h

B = 110 km/h

A & B drive towards each other

Solutions

a) equation

Let

t = elapsed time in hours,

D(t) = distance between two drivers

D(t) = 400 - (A+B) t  

D(t) = 400 - 200t  ......................(1)

b. graph : for graph, see attached figure.

c. Distance and time

Time:

solve for t with the distance D(t) = 0 using equation (1)

0 = 400 - 200 t

200t = 400

t = 2   hours

distance travelled by A = 2 hours * 90 km/h  = 180 km

distance travelled by B = 2 hours * 110 km/h  = 220 km

given that triangle abc is transformed two times to get triangle

a"b"c"

first abc is transformed in to a'b'c' as follows:

the coordinates of a are (1,-1) and transformed into a'(-1,1)

similarly b (4,-2) became b'(-4,2) and

c(7,-2) became c'(-7,2)

i.e. (x,y) becomes (-x,-y)

this is nothing but reflection about a point here origin.

thus first transformation is reflection on the origin.

next is exactly shifting 3 units down

source:

47.28 or 47.2857143

step-by-step explanation:

you just divide 331 by 7 and you get that answer. ( i think so tho)