The surface area of a solid is 10 square feet. The dimensions of a similar solid are three times as great as the first. The surface area of the new solid in square feet
is...
PLEASE urgent

The total surface area of the new solid in square feet is 90 square feet

Let the solid be a cube.

The surface area of a cube = 6L²

L is the length o the cube;

If the surface area of a solid is 10 square feet, then;

10 = 6L²

L² = 10/6

L = √10/6

If the dimensions of a similar solid are  three times as great as the first, then;

New length Ln = 3√10/6

Total surface area of the new solid = 6Ln²

Total surface area of the new solid = 6(3√10/6)²

Total surface area of the new solid = 6(9*10/6)

Total surface area of the new solid = 6(90/6)

Total surface area of the new solid = 90 square feet

This shows that the total surface area of the new solid in square feet is 90 square feet

Learn more here: link

90 ft²

Step-by-step explanation:

Given the sides of similar figures in the ratio a : b, then

ratio of areas = a² : b²

Here ratio of sides = 1 : 3 , thus

ratio of areas = 1² : 3² = 1 : 9

That is the surface area of the new solid is 9 times the first

SA = 9 × 10 = 90 ft²

7

step-by-step explanation:

the answer would be 7