A rocket is launched from a tower. The height of the rocket, y in feet, is related to the time after launch, x in seconds, by the given equation. Using this equation, find the maximum height reached by the rocket (write out the full number). y=-16x^2+147x+118 The Maximum Height reached by the rocket is feet.

The Maximum Height reached by the rocket is 456.1 feet

Step-by-step explanation:

In order to calculate the maximum height reached by the rocket we would have to calculate first the derivative of y=-16x^2+147x+118 as follows:

derivative of y=-16x^2+147x+118=y'=dy/dx=d/dx(-16x^2+147x+118)

y'=-32x+147

Therefore, x=147/32

x=4.59375

Therefore, the maximum height reached by the rocket=-16*4.59375^2 + 147*4.59375 + 118

The maximum height reached by the rocket=456.1

The Maximum Height reached by the rocket is 456.1 feet

it would be 6xy and -16xy.

step-by-step explanation:

given that there are two triangles j'k'l' and jkl>

the former is got by dilating the second one.

when drawn on a grid, (graph paper) coordinates of vertices of first triangle is

(6,12)j, (9,6)k and (12,9)l

side jk has length = distance between j and k

=

side j'k'=distance between j' and k'

=

ie j'k'l' has sides 1/3 of that of corresponding sides of jkl.

hence scale factor of 1/3 is used to get j'k'l'from jkl