find the sum of even numbers between 1001 and 10,000 (Arithmetic progressions) DO STEP BY STEP PLEASE

Step-by-step explanation:

arithmetic progression

even numbers between 1001 and 10000

1002,1004,9998

Tn=a+(n-1)d

Tn = 9998 last term in the progression of even numbers

a = 1002 first term

d = 2 distance

9998=1002+(n-1)(2)

8996=2n-2

8998=2n

n = 4499 the number of terms

sum = n/2 (a+Tn) = 4499/2(1002+9998)

= (4499/2)(11000) = 24744500

Logic:

notice what happens when you add the first and last terms

1002+9998=11000

1004+9996=11000

answer: h

step-by-step explanation:

the answer for this question is : 360°

step-by-step explanation:

we have been given a triangle   we need to tell which one of these is a triangle below to map onto itself.

360° rotation is the complete rotation which eventually leads to the same figure which is given.

the correct will be, that is 360° that will cause the triangle below to map onto itself.