In a circle PQ & RS are two chords bisecting each other, prove that the two parts of one chord are equal to the two parts of the other.

see proof below

Step-by-step explanation:

Let

p1,p2 = half lengths of chord p

q1,q2 = half length of chord q

By the intersecting chord theorem,

p1*p2 = q1*q2,    substituting p1=p2, q1=q2

p1^2 = q1*2

Take square-roots and reject negative roots

p1 = q1

therefore

p1=p2 = q1=q2, or

two parts of one chord are equal to the two parts of the other.

to find the perimeter of the rectangle this is the expression:

x-9+x-9+3x-4+3x-4=138

if we simplify it:

8x-26=138

remember, 138 is what it all adds up to

the length is 11.5cm

the width is 57.5cm

the area is 661.25cm^2

the answers might not be correct use at own risk

a - base

b - exponent

so,