let (-3,-7) be a point on the terminal side of theta. find the exact values of sin theta, sec theta, and tan theta

The exact values of sinθ = -7/√58.

The exact value of  secθ = -√58/3 and

The exact value of tanθ = 7/3

Step-by-step explanation:

Given that a point on the terminal side is of an angle is (x,y) and we are given (-3, -7). So x = -3 and y = -7. The length of its terminal side is given by r = √(x² + y²) = √((-3)² + (-7)²) = √(9 + 49) = √58

We know that sinθ = y/r.

So, sinθ = y/r = -7/√58

We know that secθ = 1/cosθ = 1/x/r = r/x

So, secθ = r/x = √58/-3 = -√58/3

We know that tanθ = y/x.

So, tanθ = y/x = -7/-3 = 7/3

So, the exact values of sinθ = -7/√58.

The exact value of  secθ = -√58/3 and

The exact value of tanθ = 7/3

the correct functions are

h(x) = 3x + 2  

g(x) = 2^x

step-by-step explanation:

i proceed to calculate the different values ​​of k (x)

case 1)  k(x) = g(x) ∘ h(x)

g(x) ∘ h(x)=g(h(x))

k(x) = [2]^[3x + > is the option  4. k(x) = 2^(3x + 2 )

case 2)  k(x) = g(x) + h(x)

k(x) = [2^x]+[3x + 2]=2^x+3x+> is the option  1.) k(x) = 2^x + 3x + 2

case 3)k(x) = h(x) ÷ g(x)

k(x) =  [3x + 2]/[2^x]=3x/(2^x)+2/(2^x)=3x*(2^-x)+2^(1-x)

is the option  3.)   k(x) = (3x)2^(-x) + 2^(-x + 1 )

case 4)k(x) = g(x) - h(x)

k(x) =  [2^x]-[3x + 2]=2^x-3x-> is the option  2.) k(x) = 2^x - 3x - 2 

case 5)  k(x) = g(x) × h(x)

k(x) = [2^x]*[3x + > is the option  5.) k(x) = 2^x(3x + 2)

case 6)k(x) = h(x) ∘ g(x)

h(x) ∘ g(x)=h(g(x))

k(x)=3*[2^x]+> is the option  6. k(x) = 3(2^x) +2

yes the total will be same because in both of them the expression.is rearranged but their sign remains the same hence it hss just been shuffled