There are 4 red balls and 6 green balls in a bag. You reach in the bag and take out 3 balls without looking.
What is the probability that all three of the balls you take out are red?

From the question, in the bag there are;

4 red balls

6 green balls

10 balls in total.

Now, reaching in the bag and taking out 3 balls without looking, the probability that all three balls are red, can be analyzed as follows;

All three red means;

The first ball is red,

The second ball is red and;

The third ball is red.

i. First you take out a ball from a total of 10 balls. The probability P⁰(R) of having a red ball is given as;

P⁰(R) =

Since there are 4 red balls, the possible-space is 4

Also, since there are a total of 10 balls, the total-space is 10

P⁰(R) =

ii. Secondly, you take out a ball from a remaining total of 9 balls. The probability P¹(R) of still having a red ball is given as;

P¹(R) =

Since there are 3 red balls remaining, the possible-space is 3

Also, since there are a remaining total of 9 balls, the total-space is 9

P¹(R) =

iii. Thirdly, you take out a ball from a remaining total of 8 balls. The probability P²(R) of still having a red ball is given as;

P²(R) =

Since there are 2 red balls remaining, the possible-space is 2

Also, since there are a remaining total of 8 balls, the total-space is 8

P²(R) =

Therefore, the probability P(R) of taking out three red balls without looking is given by the product of the probabilities described above. i.e

P(R) = P⁰(R) x P¹(R) x P²(R)

P(R) =

step-by-step explanation:

consider an orange peel: if you want to try and lay it flat, you have to stretch it, we know exactly how things are being stretched or squashed at any given point. we have many different map projections because each has different patterns of some projections can even preserve certain features of the earth without

answer: it is a.,b.,d.

step-by-step explanation: