What is the center of the circle with the equation (x-1)^2 + (y+3)^2= 9? a (1,3) b (-1,3) c (-1,-3) d (1,-3)

The center is ( 1,-3) and the radius is 3

Step-by-step explanation:

The equation of a circle can be written in the form

( x-h)^2 + ( y-k) ^2 = r^2 where ( h,k) is the center and r is the radius

(x-1)^2 + (y+3)^2= 9

(x-1)^2 + (- -3)^2= 3^2

The center is ( 1,-3) and the radius is 3

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