60 points Lana uses factoring by grouping to factor the polynomial 8x2y−10xy2+12x−15y. Her work is shown below, but the last two lines of work are missing.

8x2y−10xy2+12x−15y

(8x2y−10xy2)+(12x−15y)

__[blank 1]__

__[blank 2]__

Select one statement for each blank to correctly complete Lana’s work.

blank 1: 2xy(4x−5y)+3(4x−5y)

blank 1: −4x(2xy+3)+5y(2xy+3)

blank 2: (2xy−3)(4x+5y)

blank 1: −2xy(4x+5y)−3(4x+5y)

blank 2: (2xy+3)(4x−5y)

blank 2: −(2xy+3)(4x−5y

NEED PROOF FOR POINTS

blank 1: 2xy(4x-5y)+3(4x-5y)

blank 2: (2xy+3)(4x-5y)

Step-by-step explanation:

Using factoring group to factor the polynomial 8x²y−10xy²+12x−15y

Step 1: Group the polynomial function

(8x²y−10xy²)+(12x−15y)

Step 2: Factor the common value and variables from the functions in parentheses.

= (2xy*4x - 2xy(5y)) + (3(4x) - 3(5y))

= 2xy(4x-5y)+3(4x-5y)

Step 3: Rearrange the expression by selecting one of the function in parentheses and combine those not in parenthesis.

(2xy+3)(4x-5y)

The final expression gives the factor form of the polynomial.

Hence the statement for each blank that correctly completes Lana's work are;

blank 1: 2xy(4x-5y)+3(4x-5y)

blank 2: (2xy+3)(4x-5y)

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step-by-step explanation:

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make sure you have version 2.50

try looking in the very back of the book : )

step-by-step explanation:

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